Results of JEE (Advanced) 2018 declared

NEW DELHI
10 Jun 2018

The Indian Institute of Technology, Kanpur declared results of Joint Entrance Examination (JEE) (Advanced)- 2018 on the website https://www.jeeadv.ac.in/ today. In 2018, a total of 11,279 seats are being offered in the IITs. As in earlier years, supernumerary seats will be created to accommodate foreign candidates along with DS candidates (with a restriction of maximum 2 DS candidates per IIT) who qualify JEE (Advanced) 2018. This year (i.e., in 2018), 800 supernumerary seats have been created specifically for female candidates in the IITs in order to improve the gender balance in IITs and as per directives of the MHRD, Government of India. As per provisions, total supernumerary seats created cannot exceed 10% of the total seats being offered in the IITs.
A total number of 1,55,158 candidates appeared in both papers 1 and 2 in JEE (Advanced) 2018. A total no. of 18138 candidates have qualified JEE (Advanced) 2018, i.e., 18138 candidates scored above the cut‐offs required for qualification. This is more than 1.6 times the number of seats that are being offered. Of the total qualified candidates, 2076 are females.
Mr. Pranav Goyal is the top ranker in Common Rank List (CRL) in JEE (Advanced) 2018 by obtaining 337 marks out of 360 marks. Ms. Meenal Parakh is the top ranked female candidate with CRL 6 by obtaining 318 marks out of 360 marks. As per details, 16,062 boys qualified in the exams while around 2076 girls were declared qualified. Total number of qualified general (GEN) candidates: 8794, total number of qualified OBC candidates: 3140, total number of qualified SC candidates: 4709 and total number of qualified ST candidates: 1495. (PIB)